Which of the following definite integrals could be used to calculate the total area bounded by the graph of y = sin(x), the xaxis, x = 0, and x = π a) ∫ from π to 0 sin(x)dx b) ∫ from π to 0 sin(x)dx c) 2∫ from π to 0 You can view more similar questions or ask a new questionIf Y = Sin1 X Cos1x Find (Dy)/(Dx) CBSE CBSE (Commerce) Class 12 Question Papers 1786 Textbook Solutions Important Solutions 3417 Question Bank Solutions Concept Notes & Videos 532 Time Tables 18 Syllabus Advertisement Remove all adsFind dy/dx y=x \sin x^{2} 🚨 Hurry, space in our FREE summer bootcamps is running out 🚨
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30.if y=(sin x)^(x)+x^(cos x) find (dy)/(dx)-In the diagram above , XZ is the diameter of the circle XZW, with center O and r PQR is the diagram of a semicircle RSP with centre at Q and radius of length 35 If y = 3 cos 4x, dy/dx equals In the figure, XYZ is a triangle with XY = 5cm, XZ = 2cm and XZ is produced to E If x varies directly as y 3 and x = 2 when y = 1, find x when yRead it Question Find dy/dx by implicit differentiation x sin(y) y sin(x) = 2 x cos(y) sin(x) y' x sin(y) y cos(x) Need Help?
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solve (cosx tany cos (xy))dx (sin x sec 2 ycos (xy))dy=0 differentialequation derivatives asked in CALCULUS by linda ScholarCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyCalculus Find dy/dx y=sin (cos (x)) y = sin(cos (x)) y = sin ( cos ( x)) Differentiate both sides of the equation d dx (y) = d dx (sin(cos(x))) d d x ( y) = d d x ( sin ( cos ( x))) The derivative of y y with respect to x x is y' y ′ y' y ′ Differentiate the right side of the equation Tap for more steps
If sin x (dy/dx)y cos x=x sinx, then (y1) sin x= (A) cx sinx (B) cx cosx cx cosx (D) cx sinx Check Answer and Solution for above question f Answered Solved Solve differential equation sin(x) dy/dx(cos(x))y=0, y((7pi)/6)=2Y = sin x cos x 5 dy/dx = cos x sin x d2y/dx^2 = sin x cos x Further, the maximum occurs at cos x sin x or cos x = sin x or x = 45⁰ The maximum value of y = sin 45 cos 45 5 =
Solve (cosxcosycotx)dxsinxsinydy=0 A sin x cos y = ln (c cos x) B sin x cos y = ln (c sin x) C sin x cos y = ln (c sin x) D sin x cos y = ln (c cos x) Problem Answer The solution is sin x cos y = ln (c sin x) View Solution Latest Problem Solving in Differential Equations y=tan^1(sin(x)cos(x)) dy/dx=d/dx(tan^1(sin(x)cos(x))) = 1/1(sinxcosx)^2 x d/dx(sinxcosx) = 1/1(sinxcosx)^2 x cosxsinx = (cosxsinx)/(sinxcosx)^2Y = (sin x) x ∴ log y = log (sin x) x ∴ log y = x log sin x ∴ `1/y dy/dx = x 1/sin x cos x log sin x1` ∴ `dy/dx = y x cot x log sin x `
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Y = d d x ( sin x × log e x) In this differentiation problem, the variable y represents a function in x Hence, it can be differentiated with respect to x and do not think that y is a constant Therefore, the function y can be differentiated by the derivative rule of logarithms 1 y × d y d x = d d x ( sinImage transcriptions ( 2 x y cos x 2 _ 2 x y 1 ) dx ( sin x 2 x 2 ) dy = 0 first order linear ordinary differential Equates A first order linear ODE has the form y' ( 4) p(xjy = 9 ( x ) let y be the dependent variable Divide by dx If zug coslay any ( sin 123 29 dy da sub stitude with yo rewrite this into form of linear ODE y 2 2 ( cos (29 1 ) y 1 = 212 sin (my sin 107Differentiating both sides with respect to x, we get − sin ( x y ) { 1 d x d y } = y cos x sin x d x d y − sin ( x y ) − sin ( x y ) d x d y = y cos x sin x d x d y
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Solution of dy/dx = (xlogx^2 x)/(siny ycosy) is (A) ysiny = x^2logx c asked in Differential equations by AmanYadav ( 556k points) differential equationsFind the general solution to sin(x) dy/dx cos(x) y = cos(6 x) y(x) = Find the unique solution that satisfies the initial condition y(?/2) = 4 y(x) = For this solution, d/ dx (?/2) = Hint Use the differential equation and the value of y(?/2) to find dy dt (?/2) dy/dx=(xtanx1secx)secxcos^2y We will use the Usual & the Rule of Implicit Differentiation xcosy=sin(xy)=sinxcosycosxsiny, (xsinx)cosy=cosxsiny Dividing by cosx*cosy, we get, (xsinx)/cosx=siny/cosy x/cosxsinx/cosx=siny/cosy, ie, tany=xsecxtanx d/dx(tany)=d/dx(xsecxtanx) sec^2y*dy/dx=x(secxtanx)1*secxsec^2x, =(xtanx1secx)secx
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If it is y= (sinx)^0 then dy/dx= 0 coz then y=1 and if it is y=sin (x^0) even then answer would be one because the y=sin1 now sin 1 here is a constant and differentiation of constants is 0 so any ways y=sinx^0 its dy/dx =0 Hope this helpsFind dy/dx by implicit differentiation x sin(y) y sin(x) = 2 x cos(y) sin(x) y' x sin(y) y cos(x) Need Help?Find dy/dx when y=x^(cos x) (sin x)^ tan x Let y1=x cosx taking log on boths ides, we get logy1=cosxlogx now diffwrto x , we get (1/y1)dy1/dx=cosx(1/x)
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Find dy/dx if y = log(sin x) Get the answer to this question and access a vast question bank that is tailored for studentsY = sin x cos x 5 dy/dx = cos x sin x d2y/dx^2 = sin x cos x Further, the maximum occurs at cos x sin x or cos x = sin x or x = 45⁰ The maximum value of y = sin 45 cos 45 5 = Solving for the derivatives brought upon us by the Product Rule math (\sin x)\ln\sin x (\frac {1} {\sin x}\cdot\cos x)\cos x = \frac {1} {y}\cdot\frac {dy} {dx} /math As a quick reminder, the derivative of the natural log of anything is math\frac {d} {dx} ln f (x) = \frac {1} {f (x)}\cdot f' (x) /math
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